2v^2+128=32v

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Solution for 2v^2+128=32v equation:


Simplifying
2v2 + 128 = 32v

Reorder the terms:
128 + 2v2 = 32v

Solving
128 + 2v2 = 32v

Solving for variable 'v'.

Reorder the terms:
128 + -32v + 2v2 = 32v + -32v

Combine like terms: 32v + -32v = 0
128 + -32v + 2v2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(64 + -16v + v2) = 0

Factor a trinomial.
2((8 + -1v)(8 + -1v)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(8 + -1v)' equal to zero and attempt to solve: Simplifying 8 + -1v = 0 Solving 8 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1v = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1v = 0 + -8 -1v = 0 + -8 Combine like terms: 0 + -8 = -8 -1v = -8 Divide each side by '-1'. v = 8 Simplifying v = 8

Subproblem 2

Set the factor '(8 + -1v)' equal to zero and attempt to solve: Simplifying 8 + -1v = 0 Solving 8 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1v = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1v = 0 + -8 -1v = 0 + -8 Combine like terms: 0 + -8 = -8 -1v = -8 Divide each side by '-1'. v = 8 Simplifying v = 8

Solution

v = {8, 8}

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